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初中數(shù)學(xué)魯教版七年級(jí)上冊(cè)《第五章 位置與坐標(biāo) 1 確定位置》教學(xué)設(shè)計(jì)教案
1、通過(guò)同位之間互說(shuō)座位位置，檢測(cè)知識(shí)目標(biāo)2、3的達(dá)成效果。2、通過(guò)導(dǎo)學(xué)案上的探究一，檢測(cè)知識(shí)目標(biāo)2、3的達(dá)成效果。 3、通過(guò)探究二，檢測(cè)知識(shí)目標(biāo)1、3的達(dá)成效果。 4、通過(guò)課堂反饋，檢測(cè)總體教學(xué)目標(biāo)的達(dá)成效果。本節(jié)課遵循分層施教的原則，以適應(yīng)不同學(xué)生的發(fā)展與提高，針對(duì)學(xué)生回答問(wèn)題本著多鼓勵(lì)、少批評(píng)的原則，具體從以下幾方面進(jìn)行評(píng)價(jià)：1、通過(guò)學(xué)生獨(dú)立思考、參與小組交流和班級(jí)集體展示，教師課堂觀察學(xué)生的表現(xiàn)，了解學(xué)生對(duì)知識(shí)的理解和掌握情況。教師進(jìn)行適時(shí)的反應(yīng)評(píng)價(jià)，同時(shí)促進(jìn)學(xué)生的自評(píng)與互評(píng)。2、通過(guò)設(shè)計(jì)課堂互說(shuō)座位、探究一、二及達(dá)標(biāo)檢測(cè)題，檢測(cè)學(xué)習(xí)目標(biāo)達(dá)成情況，同時(shí)有利于學(xué)生完成對(duì)自己的評(píng)價(jià)。3.通過(guò)課后作業(yè)，了解學(xué)生對(duì)本課時(shí)知識(shí)的掌握情況，同時(shí)又能檢測(cè)學(xué)生分析解決問(wèn)題的方法和思路，完成教學(xué)反饋評(píng)價(jià)。
【高教版】中職數(shù)學(xué)拓展模塊：2.2《雙曲線》教學(xué)設(shè)計(jì)
教學(xué)準(zhǔn)備 1. 教學(xué)目標(biāo) 知識(shí)與技能掌握雙曲線的定義，掌握雙曲線的四種標(biāo)準(zhǔn)方程形式及其對(duì)應(yīng)的焦點(diǎn)、準(zhǔn)線．過(guò)程與方法掌握對(duì)雙曲線標(biāo)準(zhǔn)方程的推導(dǎo)，進(jìn)一步理解求曲線方程的方法——坐標(biāo)法．通過(guò)本節(jié)課的學(xué)習(xí)，提高學(xué)生觀察、類比、分析和概括的能力．情感、態(tài)度與價(jià)值觀通過(guò)本節(jié)的學(xué)習(xí)，體驗(yàn)研究解析幾何的基本思想，感受圓錐曲線在刻畫(huà)現(xiàn)實(shí)和解決實(shí)際問(wèn)題中的作用，進(jìn)一步體會(huì)數(shù)形結(jié)合的思想．2. 教學(xué)重點(diǎn)/難點(diǎn) 教學(xué)重點(diǎn)雙曲線的定義及焦點(diǎn)及雙曲線標(biāo)準(zhǔn)方程．教學(xué)難點(diǎn)在推導(dǎo)雙曲線標(biāo)準(zhǔn)方程的過(guò)程中，如何選擇適當(dāng)?shù)淖鴺?biāo)系． 3. 教學(xué)用具 多媒體4. 標(biāo)簽
高教版中職數(shù)學(xué)基礎(chǔ)模塊下冊(cè)：8.4《圓》教學(xué)設(shè)計(jì)
教 學(xué) 過(guò) 程教師 行為學(xué)生 行為教學(xué) 意圖時(shí)間 *揭示課題 8．4 圓（二） *創(chuàng)設(shè)情境 興趣導(dǎo)入 【知識(shí)回顧】 我們知道，平面內(nèi)直線與圓的位置關(guān)系有三種（如圖8-21）： （1）相離：無(wú)交點(diǎn)； （2）相切：僅有一個(gè)交點(diǎn)； （3）相交：有兩個(gè)交點(diǎn)． 并且知道，直線與圓的位置關(guān)系，可以由圓心到直線的距離d與半徑r的關(guān)系來(lái)判別（如圖8-22）： （1）：直線與圓相離； （2）：直線與圓相切； （3）：直線與圓相交. 介紹 講解 說(shuō)明 質(zhì)疑 引導(dǎo) 分析 了解 思考 思考 帶領(lǐng) 學(xué)生 分析 啟發(fā) 學(xué)生思考 0 15*動(dòng)腦思考 探索新知 【新知識(shí)】 設(shè)圓的標(biāo)準(zhǔn)方程為 ， 則圓心C(a，b)到直線的距離為 ． 比較d與r的大小，就可以判斷直線與圓的位置關(guān)系． 講解 說(shuō)明 引領(lǐng) 分析 思考 理解 帶領(lǐng) 學(xué)生 分析 30*鞏固知識(shí) 典型例題 【知識(shí)鞏固】 例6 判斷下列各直線與圓的位置關(guān)系： ⑴直線, 圓； ⑵直線,圓． 解?、?由方程知，圓C的半徑，圓心為． 圓心C到直線的距離為 , 由于，故直線與圓相交． ⑵ 將方程化成圓的標(biāo)準(zhǔn)方程，得 ． 因此，圓心為，半徑．圓心C到直線的距離為 , 即由于，所以直線與圓相交． 【想一想】 你是否可以找到判斷直線與圓的位置關(guān)系的其他方法？ *例7 過(guò)點(diǎn)作圓的切線，試求切線方程． 分析 求切線方程的關(guān)鍵是求出切線的斜率．可以利用原點(diǎn)到切線的距離等于半徑的條件來(lái)確定． 解 設(shè)所求切線的斜率為，則切線方程為 ， 即 ． 圓的標(biāo)準(zhǔn)方程為 ， 所以圓心，半徑． 圖8－23 圓心到切線的距離為 ， 由于圓心到切線的距離與半徑相等，所以 ， 解得 ． 故所求切線方程（如圖8-23）為 ， 即 或． 說(shuō)明 例題7中所使用的方法是待定系數(shù)法，在利用代數(shù)方法研究幾何問(wèn)題中有著廣泛的應(yīng)用． 【想一想】 能否利用“切線垂直于過(guò)切點(diǎn)的半徑”的幾何性質(zhì)求出切線方程？ 說(shuō)明 強(qiáng)調(diào) 引領(lǐng) 講解 說(shuō)明 引領(lǐng) 講解 說(shuō)明 觀察 思考 主動(dòng) 求解 思考 主動(dòng) 求解 通過(guò)例題進(jìn)一步領(lǐng)會(huì) 注意 觀察 學(xué)生 是否 理解 知識(shí) 點(diǎn) 50
人教版高中數(shù)學(xué)選修3超幾何分布教學(xué)設(shè)計(jì)
探究新知問(wèn)題1：已知100件產(chǎn)品中有8件次品，現(xiàn)從中采用有放回方式隨機(jī)抽取4件．設(shè)抽取的4件產(chǎn)品中次品數(shù)為X，求隨機(jī)變量X的分布列.（1）：采用有放回抽樣，隨機(jī)變量X服從二項(xiàng)分布嗎？采用有放回抽樣，則每次抽到次品的概率為0.08，且各次抽樣的結(jié)果相互獨(dú)立,此時(shí)X服從二項(xiàng)分布,即X～B(4，0.08).（2）：如果采用不放回抽樣，抽取的4件產(chǎn)品中次品數(shù)X服從二項(xiàng)分布嗎？若不服從，那么X的分布列是什么？不服從，根據(jù)古典概型求X的分布列.解：從100件產(chǎn)品中任取4件有 C_100^4 種不同的取法，從100件產(chǎn)品中任取4件，次品數(shù)X可能取0,1,2,3,4.恰有k件次品的取法有C_8^k C_92^(4-k)種.一般地，假設(shè)一批產(chǎn)品共有N件，其中有M件次品．從N件產(chǎn)品中隨機(jī)抽取n件(不放回），用X表示抽取的n件產(chǎn)品中的次品數(shù)，則X的分布列為P(X＝k）＝CkM Cn－kN－M CnN ，k＝m，m＋1，m＋2，…，r.其中n，N，M∈N*，M≤N，n≤N，m＝max{0，n－N＋M}，r＝min{n，M}，則稱隨機(jī)變量X服從超幾何分布．
人教版高中數(shù)學(xué)選修3正態(tài)分布教學(xué)設(shè)計(jì)
3.某縣農(nóng)民月均收入服從N(500,202)的正態(tài)分布,則此縣農(nóng)民月均收入在500元到520元間人數(shù)的百分比約為 . 解析:因?yàn)樵率杖敕恼龖B(tài)分布N(500,202),所以μ=500,σ=20,μ-σ=480,μ+σ=520.所以月均收入在[480,520]范圍內(nèi)的概率為0.683.由圖像的對(duì)稱性可知,此縣農(nóng)民月均收入在500到520元間人數(shù)的百分比約為34.15%.答案:34.15%4.某種零件的尺寸ξ(單位:cm)服從正態(tài)分布N(3,12),則不屬于區(qū)間[1,5]這個(gè)尺寸范圍的零件數(shù)約占總數(shù)的 . 解析:零件尺寸屬于區(qū)間[μ-2σ,μ+2σ],即零件尺寸在[1,5]內(nèi)取值的概率約為95.4%,故零件尺寸不屬于區(qū)間[1,5]內(nèi)的概率為1-95.4%=4.6%.答案:4.6%5. 設(shè)在一次數(shù)學(xué)考試中,某班學(xué)生的分?jǐn)?shù)X~N(110,202),且知試卷滿分150分,這個(gè)班的學(xué)生共54人,求這個(gè)班在這次數(shù)學(xué)考試中及格(即90分及90分以上)的人數(shù)和130分以上的人數(shù).解:μ=110,σ=20,P(X≥90)=P(X-110≥-20)=P(X-μ≥-σ),∵P(X-μσ)≈2P(X-μ130)=P(X-110>20)=P(X-μ>σ),∴P(X-μσ)≈0.683+2P(X-μ>σ)=1,∴P(X-μ>σ)=0.158 5,即P(X>130)=0.158 5.∴54×0.158 5≈9(人),即130分以上的人數(shù)約為9人.
【高教版】中職數(shù)學(xué)拓展模塊：2.3《拋物線》教學(xué)設(shè)計(jì)
一、教學(xué)目標(biāo)(一)知識(shí)教育點(diǎn)使學(xué)生掌握拋物線的定義、拋物線的標(biāo)準(zhǔn)方程及其推導(dǎo)過(guò)程．(二)能力訓(xùn)練點(diǎn)要求學(xué)生進(jìn)一步熟練掌握解析幾何的基本思想方法，提高分析、對(duì)比、概括、轉(zhuǎn)化等方面的能力．(三)學(xué)科滲透點(diǎn)通過(guò)一個(gè)簡(jiǎn)單實(shí)驗(yàn)引入拋物線的定義，可以對(duì)學(xué)生進(jìn)行理論來(lái)源于實(shí)踐的辯證唯物主義思想教育．二、教材分析1．重點(diǎn)：拋物線的定義和標(biāo)準(zhǔn)方程．2．難點(diǎn)：拋物線的標(biāo)準(zhǔn)方程的推導(dǎo)．三、活動(dòng)設(shè)計(jì)提問(wèn)、回顧、實(shí)驗(yàn)、講解、板演、歸納表格．四、教學(xué)過(guò)程(一)導(dǎo)出課題我們已學(xué)習(xí)了圓、橢圓、雙曲線三種圓錐曲線．今天我們將學(xué)習(xí)第四種圓錐曲線——拋物線，以及它的定義和標(biāo)準(zhǔn)方程．課題是“拋物線及其標(biāo)準(zhǔn)方程”．首先，利用籃球和排球的運(yùn)動(dòng)軌跡給出拋物線的實(shí)際意義，再利用太陽(yáng)灶和拋物線型的橋說(shuō)明拋物線的實(shí)際用途。
【高教版】中職數(shù)學(xué)拓展模塊：3.5《正態(tài)分布》教學(xué)設(shè)計(jì)
教學(xué)目的：理解并熟練掌握正態(tài)分布的密度函數(shù)、分布函數(shù)、數(shù)字特征及線性性質(zhì)。教學(xué)重點(diǎn)：正態(tài)分布的密度函數(shù)和分布函數(shù)。教學(xué)難點(diǎn)：正態(tài)分布密度曲線的特征及正態(tài)分布的線性性質(zhì)。教學(xué)學(xué)時(shí)：2學(xué)時(shí)教學(xué)過(guò)程:第四章 正態(tài)分布§4.1 正態(tài)分布的概率密度與分布函數(shù)在討論正態(tài)分布之前，我們先計(jì)算積分。首先計(jì)算。因?yàn)?利用極坐標(biāo)計(jì)算)所以。記，則利用定積分的換元法有因?yàn)?，所以它可以作為某個(gè)連續(xù)隨機(jī)變量的概率密度函數(shù)。定義 如果連續(xù)隨機(jī)變量的概率密度為則稱隨機(jī)變量服從正態(tài)分布,記作,其中是正態(tài)分布的參數(shù)。正態(tài)分布也稱為高斯（Gauss）分布。
【高教版】中職數(shù)學(xué)拓展模塊：2.1《橢圓》優(yōu)秀教學(xué)設(shè)計(jì)
本人所教的兩個(gè)班級(jí)學(xué)生普遍存在著數(shù)學(xué)科基礎(chǔ)知識(shí)較為薄弱，計(jì)算能力較差，綜合能力不強(qiáng)，對(duì)數(shù)學(xué)學(xué)習(xí)有一定的困難。在課堂上的主體作用的體現(xiàn)不是太充分，但是他們能意識(shí)到自己的不足，對(duì)數(shù)學(xué)課的學(xué)習(xí)興趣高，積極性強(qiáng)。 學(xué)生在學(xué)習(xí)交往上表現(xiàn)為個(gè)別化學(xué)習(xí)，課堂上較為依賴?yán)蠋煹囊龑?dǎo)。學(xué)生的群體性小組交流能力與協(xié)同討論學(xué)習(xí)的能力不強(qiáng)，對(duì)學(xué)習(xí)資源和知識(shí)信息的獲取、加工、處理和綜合的能力較低。在教學(xué)中盡量分析細(xì)致，減少跨度較大的環(huán)節(jié)，對(duì)重要的推導(dǎo)過(guò)程采用板書(shū)方式逐步進(jìn)行，力求讓絕大多數(shù)學(xué)生接受。 1.理解橢圓標(biāo)準(zhǔn)方程的推導(dǎo)；掌握橢圓的標(biāo)準(zhǔn)方程；會(huì)根據(jù)條件求橢圓的標(biāo)準(zhǔn)方程，會(huì)根據(jù)橢圓的標(biāo)準(zhǔn)方程求焦點(diǎn)坐標(biāo). 2.通過(guò)橢圓圖形的研究和標(biāo)準(zhǔn)方程的討論，使學(xué)生掌握橢圓的幾何性質(zhì)，能正確地畫(huà)出橢圓的圖形，并了解橢圓的一些實(shí)際應(yīng)用。 1.讓學(xué)生經(jīng)歷橢圓標(biāo)準(zhǔn)方程的推導(dǎo)過(guò)程，進(jìn)一步掌握求曲線方程的一般方法，體會(huì)數(shù)形結(jié)合等數(shù)學(xué)思想；培養(yǎng)學(xué)生運(yùn)用類比、聯(lián)想等方法提出問(wèn)題. 2.培養(yǎng)學(xué)生運(yùn)用數(shù)形結(jié)合的思想，進(jìn)一步掌握利用方程研究曲線的基本方法，通過(guò)與橢圓幾何性質(zhì)的對(duì)比來(lái)提高學(xué)生聯(lián)想、類比、歸納的能力，解決一些實(shí)際問(wèn)題。 1.通過(guò)具體的情境感知研究橢圓標(biāo)準(zhǔn)方程的必要性和實(shí)際意義；體會(huì)數(shù)學(xué)的對(duì)稱美、簡(jiǎn)潔美，培養(yǎng)學(xué)生的審美情趣，形成學(xué)習(xí)數(shù)學(xué)知識(shí)的積極態(tài)度. 2.進(jìn)一步理解并掌握代數(shù)知識(shí)在解析幾何運(yùn)算中的作用，提高解方程組和計(jì)算能力，通過(guò)“數(shù)”研究“形”，說(shuō)明“數(shù)”與“形”存在矛盾的統(tǒng)一體中，通過(guò)“數(shù)”的變化研究“形”的本質(zhì)。幫助學(xué)生建立勇于探索創(chuàng)新的精神和克服困難的信心。
人教版高中數(shù)學(xué)選修3排列與排列數(shù)教學(xué)設(shè)計(jì)
4.有8種不同的菜種,任選4種種在不同土質(zhì)的4塊地里,有 種不同的種法. 解析:將4塊不同土質(zhì)的地看作4個(gè)不同的位置,從8種不同的菜種中任選4種種在4塊不同土質(zhì)的地里,則本題即為從8個(gè)不同元素中任選4個(gè)元素的排列問(wèn)題,所以不同的種法共有A_8^4 =8×7×6×5=1 680(種).答案:1 6805.用1、2、3、4、5、6、7這7個(gè)數(shù)字組成沒(méi)有重復(fù)數(shù)字的四位數(shù).(1)這些四位數(shù)中偶數(shù)有多少個(gè)?能被5整除的有多少個(gè)?(2)這些四位數(shù)中大于6 500的有多少個(gè)?解:(1)偶數(shù)的個(gè)位數(shù)只能是2、4、6,有A_3^1種排法,其他位上有A_6^3種排法,由分步乘法計(jì)數(shù)原理,知共有四位偶數(shù)A_3^1·A_6^3=360(個(gè));能被5整除的數(shù)個(gè)位必須是5,故有A_6^3=120(個(gè)).(2)最高位上是7時(shí)大于6 500,有A_6^3種,最高位上是6時(shí),百位上只能是7或5,故有2×A_5^2種.由分類加法計(jì)數(shù)原理知,這些四位數(shù)中大于6 500的共有A_6^3+2×A_5^2=160(個(gè)).
人教版高中數(shù)學(xué)選修3二項(xiàng)式定理教學(xué)設(shè)計(jì)
二項(xiàng)式定理形式上的特點(diǎn)(1)二項(xiàng)展開(kāi)式有n+1項(xiàng),而不是n項(xiàng).(2)二項(xiàng)式系數(shù)都是C_n^k(k=0,1,2,…,n),它與二項(xiàng)展開(kāi)式中某一項(xiàng)的系數(shù)不一定相等.(3)二項(xiàng)展開(kāi)式中的二項(xiàng)式系數(shù)的和等于2n,即C_n^0+C_n^1+C_n^2+…+C_n^n=2n.(4)在排列方式上,按照字母a的降冪排列,從第一項(xiàng)起,次數(shù)由n次逐項(xiàng)減少1次直到0次,同時(shí)字母b按升冪排列,次數(shù)由0次逐項(xiàng)增加1次直到n次.1．判斷(正確的打“√”，錯(cuò)誤的打“×”)(1)(a＋b)n展開(kāi)式中共有n項(xiàng)． ( )(2)在公式中，交換a，b的順序?qū)Ω黜?xiàng)沒(méi)有影響． ( )(3)Cknan－kbk是(a＋b)n展開(kāi)式中的第k項(xiàng)． ( )(4)(a－b)n與(a＋b)n的二項(xiàng)式展開(kāi)式的二項(xiàng)式系數(shù)相同． ( )[解析] (1)× 因?yàn)?a＋b)n展開(kāi)式中共有n＋1項(xiàng)．(2)× 因?yàn)槎?xiàng)式的第k＋1項(xiàng)Cknan－kbk和(b＋a)n的展開(kāi)式的第k＋1項(xiàng)Cknbn－kak是不同的，其中的a，b是不能隨便交換的．(3)× 因?yàn)镃knan－kbk是(a＋b)n展開(kāi)式中的第k＋1項(xiàng)．(4)√ 因?yàn)?a－b)n與(a＋b)n的二項(xiàng)式展開(kāi)式的二項(xiàng)式系數(shù)都是Crn.[答案] (1)× (2)× (3)× (4)√
人教版高中數(shù)學(xué)選修3全概率公式教學(xué)設(shè)計(jì)
2.某小組有20名射手，其中1，2，3，4級(jí)射手分別為2，6，9，3名.又若選1，2，3，4級(jí)射手參加比賽，則在比賽中射中目標(biāo)的概率分別為0.85，0.64，0.45，0.32，今隨機(jī)選一人參加比賽，則該小組比賽中射中目標(biāo)的概率為_(kāi)_______. 【解析】設(shè)B表示“該小組比賽中射中目標(biāo)”，Ai(i=1，2，3，4)表示“選i級(jí)射手參加比賽”，則P(B)= P(Ai)P(B|Ai)= 2/20×0.85+ 6/20 ×0.64+ 9/20×0.45+ 3/20×0.32=0.527 5.答案：0.527 53.兩批相同的產(chǎn)品各有12件和10件，每批產(chǎn)品中各有1件廢品，現(xiàn)在先從第1批產(chǎn)品中任取1件放入第2批中，然后從第2批中任取1件，則取到廢品的概率為_(kāi)_______. 【解析】設(shè)A表示“取到廢品”，B表示“從第1批中取到廢品”，有P(B)= 112，P(A|B)= 2/11 ，P(A| )= 1/11所以P(A)=P(B)P(A|B)+P( )P(A| )4．有一批同一型號(hào)的產(chǎn)品，已知其中由一廠生產(chǎn)的占 30%, 二廠生產(chǎn)的占 50% , 三廠生產(chǎn)的占 20%, 又知這三個(gè)廠的產(chǎn)品次品率分別為2% , 1%, 1%，問(wèn)從這批產(chǎn)品中任取一件是次品的概率是多少？
人教版高中數(shù)學(xué)選修3條件概率教學(xué)設(shè)計(jì)
(2)方法一:第一次取到一件不合格品,還剩下99件產(chǎn)品,其中有4件不合格品,95件合格品,于是第二次又取到不合格品的概率為4/99,由于這是一個(gè)條件概率,所以P(B|A)=4/99.方法二:根據(jù)條件概率的定義,先求出事件A,B同時(shí)發(fā)生的概率P(AB)=(C_5^2)/(C_100^2 )=1/495,所以P(B|A)=(P"(" AB")" )/(P"(" A")" )=(1/495)/(5/100)=4/99.6.在某次考試中,要從20道題中隨機(jī)地抽出6道題,若考生至少答對(duì)其中的4道題即可通過(guò);若至少答對(duì)其中5道題就獲得優(yōu)秀.已知某考生能答對(duì)其中10道題,并且知道他在這次考試中已經(jīng)通過(guò),求他獲得優(yōu)秀成績(jī)的概率.解:設(shè)事件A為“該考生6道題全答對(duì)”,事件B為“該考生答對(duì)了其中5道題而另一道答錯(cuò)”,事件C為“該考生答對(duì)了其中4道題而另2道題答錯(cuò)”,事件D為“該考生在這次考試中通過(guò)”,事件E為“該考生在這次考試中獲得優(yōu)秀”,則A,B,C兩兩互斥,且D=A∪B∪C,E=A∪B,由古典概型的概率公式及加法公式可知P(D)=P(A∪B∪C)=P(A)+P(B)+P(C)=(C_10^6)/(C_20^6 )+(C_10^5 C_10^1)/(C_20^6 )+(C_10^4 C_10^2)/(C_20^6 )=(12" " 180)/(C_20^6 ),P(E|D)=P(A∪B|D)=P(A|D)+P(B|D)=(P"(" A")" )/(P"(" D")" )+(P"(" B")" )/(P"(" D")" )=(210/(C_20^6 ))/((12" " 180)/(C_20^6 ))+((2" " 520)/(C_20^6 ))/((12" " 180)/(C_20^6 ))=13/58,即所求概率為13/58.
人教版高中數(shù)學(xué)選修3組合與組合數(shù)教學(xué)設(shè)計(jì)
解析:因?yàn)闇p法和除法運(yùn)算中交換兩個(gè)數(shù)的位置對(duì)計(jì)算結(jié)果有影響,所以屬于組合的有2個(gè).答案:B2.若A_n^2=3C_(n"-" 1)^2,則n的值為( )A.4 B.5 C.6 D.7 解析:因?yàn)锳_n^2=3C_(n"-" 1)^2,所以n(n-1)=(3"(" n"-" 1")(" n"-" 2")" )/2,解得n=6.故選C.答案:C 3.若集合A={a1,a2,a3,a4,a5},則集合A的子集中含有4個(gè)元素的子集共有 個(gè). 解析:滿足要求的子集中含有4個(gè)元素,由集合中元素的無(wú)序性,知其子集個(gè)數(shù)為C_5^4=5.答案:54.平面內(nèi)有12個(gè)點(diǎn),其中有4個(gè)點(diǎn)共線,此外再無(wú)任何3點(diǎn)共線,以這些點(diǎn)為頂點(diǎn),可得多少個(gè)不同的三角形?解:(方法一)我們把從共線的4個(gè)點(diǎn)中取點(diǎn)的多少作為分類的標(biāo)準(zhǔn):第1類,共線的4個(gè)點(diǎn)中有2個(gè)點(diǎn)作為三角形的頂點(diǎn),共有C_4^2·C_8^1=48(個(gè))不同的三角形;第2類,共線的4個(gè)點(diǎn)中有1個(gè)點(diǎn)作為三角形的頂點(diǎn),共有C_4^1·C_8^2=112(個(gè))不同的三角形;第3類,共線的4個(gè)點(diǎn)中沒(méi)有點(diǎn)作為三角形的頂點(diǎn),共有C_8^3=56(個(gè))不同的三角形.由分類加法計(jì)數(shù)原理,不同的三角形共有48+112+56=216(個(gè)).(方法二 間接法)C_12^3-C_4^3=220-4=216(個(gè)).
新人教版高中英語(yǔ)必修3Unit 1 Festivals and Celebrations教學(xué)設(shè)計(jì)二
1. Ss look at the picture and scan the passage to understand the main idea while teacher is giving the following questions to inspire Ss to think.*Where are those people?*What are they doing?*Why are they so excited?2. Ss complete the passage with the appropriate -ing form. Then discuss and check the answers with class.Answers: boring, interesting, taking, exciting, amazing3. The teacher raises questions for the students to discuss and encourages them to express their opinions.*Do you like La Tomatina? Why or why not?4. Each group representative reports the discussion result, the teacher gives feedback and the evaluation.Step 6 PracticeActivity 41. Ss complete the Ex 2 in Using structures.2. Check the answers after finishing the exercises.①The dragon boat races are the most exciting part of the Dragon Boat Festival.② The children were excited to go Easter egg hunting.③What an amazing performance! This is the best music festival I have ever been to.④We were amazed by her funny-looking hat.⑤His inspiring speech at the conference won the admiration/ favour of the audience.⑥This is a challenging game to test your memory and observation capabilities. 3. T asks Ss to finish Ex 3 and 4 in Using structures by themselves, then check the answers with class.Step 6 Homework1. Understand and master the functions and usage of the -ing form;2. Finish the other exercises in Using structures.1、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生是否理解和掌握動(dòng)詞-ing形式作定語(yǔ)和表語(yǔ)的功能和意義；2、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否在理解文段內(nèi)容的基礎(chǔ)上，根據(jù)上下文語(yǔ)境和表達(dá)邏輯，能正確運(yùn)用動(dòng)詞-ing形式描述節(jié)日慶典。3、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生是否歸納和積累用于表達(dá)情緒的相關(guān)詞匯。
新人教版高中英語(yǔ)必修3Unit 2 Morals and Virtues教學(xué)設(shè)計(jì)二
Activity 41. Students complete the task of activity 4, then teachers and students check the answers. 2. The teacher organized the students to work together and asked them to use the tables and mind maps sorted out before to retold the important choices in Lin Qiaozhi's life and their resultsStep 5 Language points1. The teacher asks the students to read the text carefully, find out the core words and long and difficult sentences in the text and draw lines, understand the use of vocabulary, and analyze the structure of long and difficult sentences. 2. The teacher explains and summarizes the usage of core vocabulary and asks the students to take notes. 3. The teacher analyzes and explains the long and difficult sentences that the students don't understand, so that the students can understand them better. Step 6 Homework1. Read the text again, in-depth understanding of the text; 2. Master the use of core vocabulary and understand the long and difficult sentences. 3. Complete relevant exercises in the guide plan. 1、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生是否理解和掌握閱讀文本中的新詞匯的意義與用法；2、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否結(jié)合文本特點(diǎn)總結(jié)林巧稚的人生原則和人格品質(zhì)特征；3、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否針對(duì)人生抉擇發(fā)表自己的看法；能否全面地、客觀地、理性地看待問(wèn)題，進(jìn)而對(duì)道德和人性有更加深入的思考和理解。
新人教版高中英語(yǔ)必修3Unit 2 Morals and virtues教學(xué)設(shè)計(jì)一
(2) students are divided into groups according to the requirements of activity 3. Each student shares a story of personal experience or hearing-witnessing kindness, and then selects the most touching story in the group and shares it with the whole class. Before the students share the story, the teacher can instruct them to use the words and sentence patterns in the box to express. For example, the words in the box can be classified:Time order: first of all, then, after that, later, finally logical relationship :so, however, although, butTeachers can also appropriately add some transitional language to enrich students' expression:Afterwards, afterwards, at last, in the end, eventuallySpatial order: next to, far from, on the left, in front ofOtherwise, nevertheless, as a result, therefore, furthermore, in addition, as well asSummary: in a word, in short, on the whole, to sum up, in briefStep 8 Homework1. Understand the definition of "moral dilemma" and establish a correct moral view;2. Accumulate vocabulary about attitudes and emotions in listening texts and use them to express your own views;3. Complete relevant exercises in the guide plan.1、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否理解理解“道德困境”的定義；2、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否通過(guò)說(shuō)話人所表達(dá)的內(nèi)容、說(shuō)話的語(yǔ)氣、語(yǔ)調(diào)等來(lái)判斷其態(tài)度和情緒；3、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否針對(duì)具體的道德困境發(fā)表自己的看法和見(jiàn)解，能否掌握聽(tīng)力理訓(xùn)練中的聽(tīng)力策略。
新人教版高中英語(yǔ)必修3Unit 3 Diverse Cultures教學(xué)設(shè)計(jì)二
(2)Consolidate key vocabulary.Ask the students to complete the exercises of activity 6 by themselves. Then ask them to check the answers with their partners.(The first language:Damage of the 1906 San Francisco earthquake and fire.A second language: Yunnan - one of the most diverse provinces in China).Step 5 Language points1. The teacher asks the students to read the text carefully, find out the more words and long and difficult sentences in the text and draw lines, understand the use of vocabulary, and analyze the structure of long and difficult sentences.2. The teacher explains and summarizes the usage of core vocabulary and asks the students to take notes.3. The teacher analyzes and explains the long and difficult sentences that the students don't understand, so that the students can understand them better.Step 6 Homework1. Read the text again, in-depth understanding of the text;2. Master the use of core vocabulary and understand the long and difficult sentences.3. Complete relevant exercises in the guide plan.1、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生是否理解和掌握閱讀文本中的新詞匯的意義與用法；2、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否結(jié)合文本特點(diǎn)了解文章的結(jié)構(gòu)和作者的寫(xiě)作邏輯；3、通過(guò)本節(jié)內(nèi)容學(xué)習(xí)，學(xué)生能否了解舊金山的城市風(fēng)貌、文化特色，以及加利福尼亞州的歷史，體會(huì)多元文化對(duì)美國(guó)的影響。
新人教版高中英語(yǔ)選修2Unit 2 Reading for writing教學(xué)設(shè)計(jì)
The theme of this section is to express people's views on studying abroad. With the continuous development of Chinese economic construction, especially the general improvement of people's living standards, the number of Chinese students studying abroad at their own expense is on the rise. Many students and parents turn their attention to the world and regard studying abroad as an effective way to improve their quality, broaden their horizons and master the world's advanced scientific knowledge, which is very important for the fever of going abroad. Studying abroad is also an important decision made by a family for their children. Therefore, it is of great social significance to discuss this issue. The theme of this section is the column discussion in the newspaper: the advantages and disadvantages of studying abroad. The discourse is about two parents' contribution letters on this issue. They respectively express their own positions. One thinks that the disadvantages outweigh the advantages, and the other thinks that the advantages outweigh the disadvantages. The two parents' arguments are well founded and logical. It is worth noting that the two authors do not express their views on studying abroad from an individual point of view, but from a national or even global point of view. These two articles have the characteristics of both letters and argumentative essays1.Guide the students to read these two articles, and understand the author's point of view and argument ideas2.Help the students to summarize the structure and writing methods of argumentative writing, and guides students to correctly understand the advantages and disadvantages of studying abroad3.Cultivate students' ability to analyze problems objectively, comprehensively and deeply
新人教版高中英語(yǔ)選修2Unit 4 Learning about Language教學(xué)設(shè)計(jì)
This section guides students to pay attention to the typical context of vocabulary use, helps students accumulate vocabulary around the key vocabulary of this unit, and uses the learned words and word chunks in different contexts to deeply understand their meaning and usage, so as to achieve the purpose of review and consolidation.The teaching design activities aim to guide students to pay attention to the typical context in which the target vocabulary is used, as well as the common vocabulary used in collocation, so that students can complete the sentence with correct words. In terms of vocabulary learning strategies, this unit focuses on cultivating students' ability to pay attention to collocation of words and to use word blocks to express meaning.For vocabulary learning, it is not enough just to know the meaning of a single word, but the most important thing is to master the common collocations of words, namely word blocks.Teachers should timely guide students to summarize common vocabulary collocation, such as verb and noun collocation, verb and preposition collocation, preposition and noun collocation, and so on.1. Guide students to understand and consolidate the meaning and usage of the vocabulary in the context, 2. Guide the students to use the unit topic vocabulary in a richer context3. Let the students sort out and accumulate the accumulated vocabulary, establishes the semantic connection between the vocabulary,4. Enable students to understand and master the vocabulary more effectivelyGuiding the Ss to use unit topic words and the sentence patterns in a richer context.
新人教版高中英語(yǔ)選修2Unit 5 Reading and thinking教學(xué)設(shè)計(jì)
The theme of this activity is to learn the first aid knowledge of burns. Burns is common in life, but there are some misunderstandings in manual treatment. This activity provides students with correct first aid methods, so as not to take them for granted in an emergency. This section guides students to analyze the causes of scald and help students avoid such things. From the perspective of text structure and collaborative features, the text is expository. Expository, with explanation as the main way of expression, transmits knowledge and information to readers by analyzing concepts and elaborating examples. This text arranges the information in logical order, clearly presents three parts of the content through the subtitle, accurately describes the causes, types, characteristics and first aid measures of burns, and some paragraphs use topic sentences to summarize the main idea, and the level is very clear.1. Guide students to understand the causes, types, characteristics and first aid methods of burns, through reading2. Enhance students’ ability to deal withburnss and their awareness of burns prevention3. Enable students to improve the ability to judge the types of texts accurately and to master the characteristics and writing techniques of expository texts.Guide students to understand the causes, types, characteristics and first aid methods of burns, through readingStep1: Lead in by discussing the related topic:1. What first-aid techniques do you know of ?CPR; mouth to mouth artificial respiration; the Heimlich Manoeuvre