[2] An important breakthrough…was… [3] Another innovation was … [4] the emphasis increasingly shifted from…to… [5] New ideas and values gradually replaced… [6] While his paintings still had religious themes… … T: All these expressions serve to show how Western painting has developed. Some of them share similar structure but with varied use of words, which makes the text vivid and more readable. 【設計意圖】主題類語言整理有助于學生類化語言應用,提高語言輸出的豐富性。處理完文本內容信息后,進入語篇信息處理,進行主題相關的詞塊歸類。引導學生快速閱讀,尋找表達相同主題(發(fā)展或者藝術)的詞和短語,再根據(jù)詞性、用法和結構進行歸類,儲備主題相關詞匯,豐富語言儲備,提升語言素養(yǎng)。 Assignment: Go online to gather more information about Chinese painting and write a short history of it. 【設計意圖】結合所學,遷移運用,根據(jù)實際語境,進行模仿性運用。在此過程中,學生嘗試借鑒已學的語言、內容、語篇結構和寫作手法來建構新文本,實現(xiàn)語篇輸出,同時關注中西藝術文化的差別,加深對優(yōu)秀文化的認同,培養(yǎng)文化意識。
本單元閱讀文本介紹了幾種簡單的英語詩歌形式,旨在讓學生能理解和欣賞英語詩歌的美,包括形式美、內容美、意義美,培養(yǎng)審美情趣,并從作品的意義美中獲得積極的人生態(tài)度和價值觀念啟示。 該文本是一則典型的說明性文本,用簡單易懂的語言向英語詩歌的初學者們介紹了五種比較簡單的英語詩歌形式。文題“A Few Simple Forms of English Poems”是整個文本的核心話題。正文內容共七段,按“總—分—總”建構。第一段為總起段,概述了英語詩歌的創(chuàng)作原因以及主要特點,涉及了形式、內容、意義等方面賞析英語詩歌的幾個主要維度;第二段至第六段分別介紹了童謠、清單詩、五行詩、俳句和唐詩五種英語詩歌形式;第七段收尾,鼓勵讀者嘗試英語詩歌創(chuàng)作。 在進行文本教學設計時,要引導學生梳理關于與詩歌要素和詩歌賞析有關的話題類語言,既包括format、rhythm、subject、image等名詞,也包括have a strong rhythm、be made up of、contain、consist of、convey這樣的動詞和動詞短語。
2. Explore the significance of the establishment of Sarek National Park.Q1: Which event is the most important one in the park’s history?Ss: The establishment of Sarek national park in 1909 is the most important one.Q2: Is it worth making a place like Sarek a national park? Give your reasons.Ss: Yes. In this way, the place can be kept in its natural state and natural beauties and other rare and valuable resources can be preserved instead of being destroyed by endless exploitation driven by profits.Q3: How does the writer organize his introduction to the history of Sarek?Ss: The writer organizes his introduction in the sequence of time, using time indicators such as “used to”, “around 9,000 years ago”, “soon after”, “following the reindeer”, and “in 1909”.Q4: What is the feature of the language used to introduce the history of the park?Ss: The introduction to the park is to provide facts, using time indicators to organize the events. Sentences starts with “third person” and passive voice is used more often, feeling objective.【設計意圖】學生尋找和梳理公園歷史上的重要事件,體會人與自然的和諧關系,評鑒介紹性語言的特點?!竞诵乃仞B(yǎng)提升點】發(fā)展自主提取、梳理文本信息能力,訓練邏輯思維和高階思維。Activity 3: Highlighting the secret of the text
1. 完成文本主要信息填空(斜體字部分設空):As a witness to farmers’ poor harvests and even a severe shortage of food, Yuan Longping was determined to devote his life to tackling this crisis. After graduation, he realized that what farmers needed most was to boost yields in the fields. Yuan was convinced that the answer lay in the creation of hybrid rice, one characteristic of which is that it usually achieve higher output than conventional crops. However, it was no easy job. The first difficulty he needed to overcome was scientists’ general assumption that this could not be done. Through trial and error, Yuan managed to generate this incredible crop. It is estimated that about 60 percent of domestic rice consumption in China was comprised of crops generated from Yuan’s hybrid strains. His innovation has enabled Chinese farmers to considerably expand their output and helped feed the world. Unwilling to retire early to a life of leisure and unconcerned about celebrity or fortune, Yuan continues to turn one vision after another into realities.2. 模仿寫作:Do some research via the Internet and introduce another agricultural scientist, Chen Risheng(陳日勝), using the structure, expressions and writing techniques you have learnt from the text “A Pioneer for All People”.【設計意圖】任務1是對文本內容和詞匯學習成效的檢測。任務2借助文本中學到的詞匯和寫作手法仿寫另一位科學家,提升學生遷移運用詞匯、文體結構和寫作方法的能力。
【教材分析】This teaching period mainly deals with reading for writing a letter of advice. Students are expected to learn the knowledge about how to write a suggestion letter. The teacher is expected to enable students to master some writing skills concerning suggestion letters and learn to write one.【教學目標與核心素養(yǎng)】1. Get students to have a good understanding of how to write a suggestion letter properly.2. Enable students to use some writing skills flexibly.3. Develop students’ writing and cooperating abilities.4. Strengthen students’ great interest in writing discourses.【教學重難點】1. How to enable students to have a good understanding of the skills of writing a suggestion letter2.How to enable students to write a good recommendation letter using some writing skills properly.【教學過程】Step 1: Lead in Begin the class with the lead-in questions: how to write a letter for advice? What kinds of aspects should be included? It is strongly recommended that the teacher should ask students to discuss the topic freely with their partners and brainstorm some ideas concerning the topic. In this way, students can come up with more ideas and avoid being nervous at the beginning of the class.Step 2: Read to discover details concerning advice letters’ writing style.The teacher is expected to ask students to read a letter offering some advice on page 18 silently and then request students to discuss the questions below.
Then have them write a short paragraph to describe and explain their changes. After that, get the Ss to exchange their drafts with their partners and use the checklist to give feedback on their drafts, and finally revise it.Step 5 Summary of how to write a wellness book1.健康書的審題步驟:第一步:明確要求該寫作屬于經驗分享,故要用第一人稱來寫;時態(tài)以一股現(xiàn)在時為主。第二步:確定段落該類文章可以從以下三個方面人手:Para.1首先表明寫作的目的Para.2自己的做法及心得體會Para.3表示期望及感謝第三步:提煉要點2.健康書常見句式:1) It is an honor for me to share my favorite sport with you,2) It makes me feel relaxed playing with my friends.3) It makes me rid myself of stress while playing with my friends.4) Moreover, it provides me a valuable chance to communicate with others.5) I we eat too little or too much, or if we choose the wrong food, we may become sick.6) We can do something to change the poor situation.Step 6Homework假如你的老師讓你在班級Wellness Bok上分享自己的親身經歷及心得,請根據(jù)以下要點寫一篇80字左右的文章1. 你喜歡的運動是什么?2. 你最喜歡的原因是什么?3. 你參加鍛煉的體會。
Step 3: Read to sum upRead it again and sum up the problems of the three students, and then write down the advice that was given from others.Step 4: Work in pairs. List your learning problems in English and brainstorm some useful advice.Useful expressions ? I don't know how to…... Is a big difficulty for me. I cannot ...? You might try …. It's very important to…? I have no idea how/what .My biggest problem is .... ? I (also) have trouble with. My advice is …. This worked for me.? l cannot understand the teachers’ English in class.Step 5 Homework:為提高我校學生的英語口語水平,我們將舉辦英語演講比賽(English- speaking contest),請你根據(jù)下面的信息,以學生會(the Students‘ Union)的名義寫一份海報,歡迎全校同學參加,屆時特邀本校美籍教師史密斯先生頒獎。? 報名時間 9月30日以前(報名:signup)? 報名地點 學生會辦公室? 比賽時間 10月9日晚7:00~9:00? 比賽地點 學校大會議室? 獎勵 前8名
教學目標知識目標:讓學生更好理解如何恰當?shù)貙懸粋€人的信息介紹,并能讓學生熟練地使用一些寫作技能。能力目標:培養(yǎng)學生的寫作能力和團隊協(xié)作能力。情感目標:提升學生對寫作的興趣。教學重難點 教學重點:如何能讓學生更好地理解個人信息介紹。教學難點:如何能讓學生通過適當?shù)厥褂靡恍懽骷寄軄韺懸黄^好的個人信息介紹。教學準備 多媒體、黑板、粉筆一、Pre-class1. Greetings2. Leading-inAsk students how to write a profile. What kinds of aspects should be included? The teacher asks students to discuss the topic with each other and put forward to much more ideas about the answer.二、While-class1. The teacher lets students to read the student profiles on Page 8 silently and then asks students to discuss the questions below.1. What is Ann like? How do you know?2. What are Thando’s hobbies?3. Where does Thando come from?4. What is Thando’s dream?5. What does “You will never see me without a book or a pen” mean?
二、典例解析例4. 用 10 000元購買某個理財產品一年.(1)若以月利率0.400%的復利計息,12個月能獲得多少利息(精確到1元)?(2)若以季度復利計息,存4個季度,則當每季度利率為多少時,按季結算的利息不少于按月結算的利息(精確到10^(-5))?分析:復利是指把前一期的利息與本金之和算作本金,再計算下一期的利息.所以若原始本金為a元,每期的利率為r ,則從第一期開始,各期的本利和a , a(1+r),a(1+r)^2…構成等比數(shù)列.解:(1)設這筆錢存 n 個月以后的本利和組成一個數(shù)列{a_n },則{a_n }是等比數(shù)列,首項a_1=10^4 (1+0.400%),公比 q=1+0.400%,所以a_12=a_1 q^11 〖=10〗^4 (1+0.400%)^12≈10 490.7.所以,12個月后的利息為10 490.7-10^4≈491(元).解:(2)設季度利率為 r ,這筆錢存 n 個季度以后的本利和組成一個數(shù)列{b_n },則{b_n }也是一個等比數(shù)列,首項 b_1=10^4 (1+r),公比為1+r,于是 b_4=10^4 (1+r)^4.
二、典例解析例10. 如圖,正方形ABCD 的邊長為5cm ,取正方形ABCD 各邊的中點E,F,G,H, 作第2個正方形 EFGH,然后再取正方形EFGH各邊的中點I,J,K,L,作第3個正方形IJKL ,依此方法一直繼續(xù)下去. (1) 求從正方形ABCD 開始,連續(xù)10個正方形的面積之和;(2) 如果這個作圖過程可以一直繼續(xù)下去,那么所有這些正方形的面積之和將趨近于多少?分析:可以利用數(shù)列表示各正方形的面積,根據(jù)條件可知,這是一個等比數(shù)列。解:設正方形的面積為a_1,后續(xù)各正方形的面積依次為a_2, a_(3, ) 〖…,a〗_n,…,則a_1=25,由于第k+1個正方形的頂點分別是第k個正方形各邊的中點,所以a_(k+1)=〖1/2 a〗_k,因此{a_n},是以25為首項,1/2為公比的等比數(shù)列.設{a_n}的前項和為S_n(1)S_10=(25×[1-(1/2)^10 ] )/("1 " -1/2)=50×[1-(1/2)^10 ]=25575/512所以,前10個正方形的面積之和為25575/512cm^2.(2)當無限增大時,無限趨近于所有正方形的面積和
課前小測1.思考辨析(1)若Sn為等差數(shù)列{an}的前n項和,則數(shù)列Snn也是等差數(shù)列.( )(2)若a1>0,d<0,則等差數(shù)列中所有正項之和最大.( )(3)在等差數(shù)列中,Sn是其前n項和,則有S2n-1=(2n-1)an.( )[答案] (1)√ (2)√ (3)√2.在項數(shù)為2n+1的等差數(shù)列中,所有奇數(shù)項的和為165,所有偶數(shù)項的和為150,則n等于( )A.9 B.10 C.11 D.12B [∵S奇S偶=n+1n,∴165150=n+1n.∴n=10.故選B項.]3.等差數(shù)列{an}中,S2=4,S4=9,則S6=________.15 [由S2,S4-S2,S6-S4成等差數(shù)列得2(S4-S2)=S2+(S6-S4)解得S6=15.]4.已知數(shù)列{an}的通項公式是an=2n-48,則Sn取得最小值時,n為________.23或24 [由an≤0即2n-48≤0得n≤24.∴所有負項的和最小,即n=23或24.]二、典例解析例8.某校新建一個報告廳,要求容納800個座位,報告廳共有20排座位,從第2排起后一排都比前一排多兩個座位. 問第1排應安排多少個座位?分析:將第1排到第20排的座位數(shù)依次排成一列,構成數(shù)列{an} ,設數(shù)列{an} 的前n項和為S_n。
二、典例解析例3.某公司購置了一臺價值為220萬元的設備,隨著設備在使用過程中老化,其價值會逐年減少.經驗表明,每經過一年其價值會減少d(d為正常數(shù))萬元.已知這臺設備的使用年限為10年,超過10年 ,它的價值將低于購進價值的5%,設備將報廢.請確定d的范圍.分析:該設備使用n年后的價值構成數(shù)列{an},由題意可知,an=an-1-d (n≥2). 即:an-an-1=-d.所以{an}為公差為-d的等差數(shù)列.10年之內(含10年),該設備的價值不小于(220×5%=)11萬元;10年后,該設備的價值需小于11萬元.利用{an}的通項公式列不等式求解.解:設使用n年后,這臺設備的價值為an萬元,則可得數(shù)列{an}.由已知條件,得an=an-1-d(n≥2).所以數(shù)列{an}是一個公差為-d的等差數(shù)列.因為a1=220-d,所以an=220-d+(n-1)(-d)=220-nd. 由題意,得a10≥11,a11<11. 即:{█("220-10d≥11" @"220-11d<11" )┤解得19<d≤20.9所以,d的求值范圍為19<d≤20.9
《奇偶性》內容選自人教版A版第一冊第三章第三節(jié)第二課時;函數(shù)奇偶性是研究函數(shù)的一個重要策略,因此奇偶性成為函數(shù)的重要性質之一,它的研究也為今后指對函數(shù)、冪函數(shù)、三角函數(shù)的性質等后續(xù)內容的深入起著鋪墊的作用.課程目標1、理解函數(shù)的奇偶性及其幾何意義;2、學會運用函數(shù)圖象理解和研究函數(shù)的性質;3、學會判斷函數(shù)的奇偶性.數(shù)學學科素養(yǎng)1.數(shù)學抽象:用數(shù)學語言表示函數(shù)奇偶性;2.邏輯推理:證明函數(shù)奇偶性;3.數(shù)學運算:運用函數(shù)奇偶性求參數(shù);4.數(shù)據(jù)分析:利用圖像求奇偶函數(shù);5.數(shù)學建模:在具體問題情境中,運用數(shù)形結合思想,利用奇偶性解決實際問題。重點:函數(shù)奇偶性概念的形成和函數(shù)奇偶性的判斷;難點:函數(shù)奇偶性概念的探究與理解.教學方法:以學生為主體,采用誘思探究式教學,精講多練。
冪函數(shù)是在繼一次函數(shù)、反比例函數(shù)、二次函數(shù)之后,又學習了單調性、最值、奇偶性的基礎上,借助實例,總結出冪函數(shù)的概念,再借助圖像研究冪函數(shù)的性質.課程目標1、理解冪函數(shù)的概念,會畫冪函數(shù)y=x,y=x2,y=x3,y=x-1,y=x 的圖象;2、結合這幾個冪函數(shù)的圖象,理解冪函數(shù)圖象的變化情況和性質;3、通過觀察、總結冪函數(shù)的性質,培養(yǎng)學生概括抽象和識圖能力.數(shù)學學科素養(yǎng)1.數(shù)學抽象:用數(shù)學語言表示函數(shù)冪函數(shù);2.邏輯推理:常見冪函數(shù)的性質;3.數(shù)學運算:利用冪函數(shù)的概念求參數(shù);4.數(shù)據(jù)分析:比較冪函數(shù)大小;5.數(shù)學建模:在具體問題情境中,運用數(shù)形結合思想,利用冪函數(shù)性質、圖像特點解決實際問題。重點:常見冪函數(shù)的概念、圖象和性質;難點:冪函數(shù)的單調性及比較兩個冪值的大?。?/p>
學生已經學習了指數(shù)運算性質,有了這些知識作儲備,教科書通過利用指數(shù)運算性質,推導對數(shù)的運算性質,再學習利用對數(shù)的運算性質化簡求值。課程目標1、通過具體實例引入,推導對數(shù)的運算性質;2、熟練掌握對數(shù)的運算性質,學會化簡,計算.數(shù)學學科素養(yǎng)1.數(shù)學抽象:對數(shù)的運算性質;2.邏輯推理:換底公式的推導;3.數(shù)學運算:對數(shù)運算性質的應用;4.數(shù)學建模:在熟悉的實際情景中,模仿學過的數(shù)學建模過程解決問題.重點:對數(shù)的運算性質,換底公式,對數(shù)恒等式及其應用;難點:正確使用對數(shù)的運算性質和換底公式.教學方法:以學生為主體,采用誘思探究式教學,精講多練。教學工具:多媒體。一、 情景導入回顧指數(shù)性質:(1)aras=ar+s(a>0,r,s∈Q).(2)(ar)s= (a>0,r,s∈Q).(3)(ab)r= (a>0,b>0,r∈Q).那么對數(shù)有哪些性質?如 要求:讓學生自由發(fā)言,教師不做判斷。而是引導學生進一步觀察.研探.
對數(shù)與指數(shù)是相通的,本節(jié)在已經學習指數(shù)的基礎上通過實例總結歸納對數(shù)的概念,通過對數(shù)的性質和恒等式解決一些與對數(shù)有關的問題.課程目標1、理解對數(shù)的概念以及對數(shù)的基本性質;2、掌握對數(shù)式與指數(shù)式的相互轉化;數(shù)學學科素養(yǎng)1.數(shù)學抽象:對數(shù)的概念;2.邏輯推理:推導對數(shù)性質;3.數(shù)學運算:用對數(shù)的基本性質與對數(shù)恒等式求值;4.數(shù)學建模:通過與指數(shù)式的比較,引出對數(shù)定義與性質.重點:對數(shù)式與指數(shù)式的互化以及對數(shù)性質;難點:推導對數(shù)性質.教學方法:以學生為主體,采用誘思探究式教學,精講多練。教學工具:多媒體。一、 情景導入已知中國的人口數(shù)y和年頭x滿足關系 中,若知年頭數(shù)則能算出相應的人口總數(shù)。反之,如果問“哪一年的人口數(shù)可達到18億,20億,30億......”,該如何解決?要求:讓學生自由發(fā)言,教師不做判斷。而是引導學生進一步觀察.研探.
《基本不等式》在人教A版高中數(shù)學第一冊第二章第2節(jié),本節(jié)課的內容是基本不等式的形式以及推導和證明過程。本章一直在研究不等式的相關問題,對于本節(jié)課的知識點有了很好的鋪墊作用。同時本節(jié)課的內容也是之后基本不等式應用的必要基礎。課程目標1.掌握基本不等式的形式以及推導過程,會用基本不等式解決簡單問題。2.經歷基本不等式的推導與證明過程,提升邏輯推理能力。3.在猜想論證的過程中,體會數(shù)學的嚴謹性。數(shù)學學科素養(yǎng)1.數(shù)學抽象:基本不等式的形式以及推導過程;2.邏輯推理:基本不等式的證明;3.數(shù)學運算:利用基本不等式求最值;4.數(shù)據(jù)分析:利用基本不等式解決實際問題;5.數(shù)學建模:利用函數(shù)的思想和基本不等式解決實際問題,提升學生的邏輯推理能力。重點:基本不等式的形成以及推導過程和利用基本不等式求最值;難點:基本不等式的推導以及證明過程.
函數(shù)在高中數(shù)學中占有很重要的比重,因而作為函數(shù)的第一節(jié)內容,主要從三個實例出發(fā),引出函數(shù)的概念.從而就函數(shù)概念的分析判斷函數(shù),求定義域和函數(shù)值,再結合三要素判斷函數(shù)相等.課程目標1.理解函數(shù)的定義、函數(shù)的定義域、值域及對應法則。2.掌握判定函數(shù)和函數(shù)相等的方法。3.學會求函數(shù)的定義域與函數(shù)值。數(shù)學學科素養(yǎng)1.數(shù)學抽象:通過教材中四個實例總結函數(shù)定義;2.邏輯推理:相等函數(shù)的判斷;3.數(shù)學運算:求函數(shù)定義域和求函數(shù)值;4.數(shù)據(jù)分析:運用分離常數(shù)法和換元法求值域;5.數(shù)學建模:通過從實際問題中抽象概括出函數(shù)概念的活動,培養(yǎng)學生從“特殊到一般”的分析問題的能力,提高學生的抽象概括能力。重點:函數(shù)的概念,函數(shù)的三要素。難點:函數(shù)概念及符號y=f(x)的理解。
例7 用描述法表示拋物線y=x2+1上的點構成的集合.【答案】見解析 【解析】 拋物線y=x2+1上的點構成的集合可表示為:{(x,y)|y=x2+1}.變式1.[變條件,變設問]本題中點的集合若改為“{x|y=x2+1}”,則集合中的元素是什么?【答案】見解析 【解析】集合{x|y=x2+1}的代表元素是x,且x∈R,所以{x|y=x2+1}中的元素是全體實數(shù).變式2.[變條件,變設問]本題中點的集合若改為“{y|y=x2+1}”,則集合中的元素是什么?【答案】見解析 【解析】集合{ y| y=x2+1}的代表元素是y,滿足條件y=x2+1的y的取值范圍是y≥1,所以{ y| y=x2+1}={ y| y≥1},所以集合中的元素是大于等于1的全體實數(shù).解題技巧(認識集合含義的2個步驟)一看代表元素,是數(shù)集還是點集,二看元素滿足什么條件即有什么公共特性。
學生在初中學習了 ~ ,但是現(xiàn)實生活中隨處可見超出 ~ 范圍的角.例如體操中有“前空翻轉體 ”,且主動輪和被動輪的旋轉方向不一致.因此為了準確描述這些現(xiàn)象,本節(jié)課主要就旋轉度數(shù)和旋轉方向對角的概念進行推廣.課程目標1.了解任意角的概念.2.理解象限角的概念及終邊相同的角的含義.3.掌握判斷象限角及表示終邊相同的角的方法.數(shù)學學科素養(yǎng)1.數(shù)學抽象:理解任意角的概念,能區(qū)分各類角;2.邏輯推理:求區(qū)域角;3.數(shù)學運算:會判斷象限角及終邊相同的角.重點:理解象限角的概念及終邊相同的角的含義;難點:掌握判斷象限角及表示終邊相同的角的方法.教學方法:以學生為主體,采用誘思探究式教學,精講多練。教學工具:多媒體。一、 情景導入初中對角的定義是:射線OA繞端點O按逆時針方向旋轉一周回到起始位置,在這個過程中可以得到 ~ 范圍內的角.但是現(xiàn)實生活中隨處可見超出 ~ 范圍的角.例如體操中有“前空翻轉體 ”,且主動輪和被動輪的旋轉方向不一致.