The theme of this section is to express people's views on studying abroad. With the continuous development of Chinese economic construction, especially the general improvement of people's living standards, the number of Chinese students studying abroad at their own expense is on the rise. Many students and parents turn their attention to the world and regard studying abroad as an effective way to improve their quality, broaden their horizons and master the world's advanced scientific knowledge, which is very important for the fever of going abroad. Studying abroad is also an important decision made by a family for their children. Therefore, it is of great social significance to discuss this issue. The theme of this section is the column discussion in the newspaper: the advantages and disadvantages of studying abroad. The discourse is about two parents' contribution letters on this issue. They respectively express their own positions. One thinks that the disadvantages outweigh the advantages, and the other thinks that the advantages outweigh the disadvantages. The two parents' arguments are well founded and logical. It is worth noting that the two authors do not express their views on studying abroad from an individual point of view, but from a national or even global point of view. These two articles have the characteristics of both letters and argumentative essays1.Guide the students to read these two articles, and understand the author's point of view and argument ideas2.Help the students to summarize the structure and writing methods of argumentative writing, and guides students to correctly understand the advantages and disadvantages of studying abroad3.Cultivate students' ability to analyze problems objectively, comprehensively and deeply
? B: Absolutely! Getting involved with Chinese cultural activities there definitely helped a lot. I got to practice my Chinese on a daily basis, and I could learn how native Chinese speakers spoke.? A: What do you feel is your biggest achievement?? B: Learning Chinese characters! I have learnt about 1,500 so far. When I first started, I didn't think it was even going to be possible to learn so many, but now I find that I can read signs, menus, and even some easy newspaper articles.? A: What are you most keen on?? B: I've really become keen on learning more about the Chinese culture, in particular Chinese calligraphy. As I have learnt Chinese characters, I have developed a great appreciation for their meaning. I want to explore Chinese characters by learning how to write them in a more beautiful way. ? A: Finally, what do you want to say to anyone interested in learning Chinese?? I have really become keen on learning more about the Chinese culture, in particular Chinese Calligraphy. As I have learnt Chinese character, I have developed a great appreciation for their meaning. I want to explore Chinese characters by learning how to write them in a more beautiful way.? A: Finally, what do you want to say to anyone interested in learning Chinese?? B: I'd say, give it a shot! While some aspects may be difficult, it is quite rewarding and you will be happy that you tried.? A: Thanks for your time. ? B:You're welcome.
1. How is Hunan cuisine somewhat different from Sichuan cuisine?The heat in Sichuan cuisine comes from chilies and Sichuan peppercorns. Human cuisine is often hotter and the heat comes from just chilies.2.What are the reasons why Hunan people like spicy food?Because they are a bold people. But many Chinese people think that hot food helps them overcome the effects of rainy or wet weather.3.Why do so many people love steamed fish head covered with chilies?People love it because the meat is quite tender and there are very few small bones.4.Why does Tingting recommend bridge tofu instead of dry pot duck with golden buns?Because bridge tofu has a lighter taste.5 .Why is red braised pork the most famous dish?Because Chairman Mao was from Hunan, and this was his favorite food.Step 5: Instruct students to make a short presentation to the class about your choice. Use the example and useful phrases below to help them.? In groups of three, discuss what types of restaurant you would like to take a foreign visitor to, and why. Then take turns role-playing taking your foreign guest to the restaurant you have chosen. One of you should act as the foreign guest, one as the Chinese host, and one as the waiter or waitress. You may start like this:? EXAMPLE? A: I really love spicy food, so what dish would you recommend?? B: I suggest Mapo tofu.? A: Really ? what's that?
This section guides students to pay attention to the typical context of vocabulary use, helps students accumulate vocabulary around the key vocabulary of this unit, and uses the learned words and word chunks in different contexts to deeply understand their meaning and usage, so as to achieve the purpose of review and consolidation.The teaching design activities aim to guide students to pay attention to the typical context in which the target vocabulary is used, as well as the common vocabulary used in collocation, so that students can complete the sentence with correct words. In terms of vocabulary learning strategies, this unit focuses on cultivating students' ability to pay attention to collocation of words and to use word blocks to express meaning.For vocabulary learning, it is not enough just to know the meaning of a single word, but the most important thing is to master the common collocations of words, namely word blocks.Teachers should timely guide students to summarize common vocabulary collocation, such as verb and noun collocation, verb and preposition collocation, preposition and noun collocation, and so on.1. Guide students to understand and consolidate the meaning and usage of the vocabulary in the context, 2. Guide the students to use the unit topic vocabulary in a richer context3. Let the students sort out and accumulate the accumulated vocabulary, establishes the semantic connection between the vocabulary,4. Enable students to understand and master the vocabulary more effectivelyGuiding the Ss to use unit topic words and the sentence patterns in a richer context.
The purpose of this section of vocabulary exercises is to consolidate the key words in the first part of the reading text, let the students write the words according to the English definition, and focus on the detection of the meaning and spelling of the new words. The teaching design includes use English definition to explain words, which is conducive to improving students' interest in vocabulary learning, cultivating their sense of English language and thinking in English, and making students willing to use this method to better grasp the meaning of words, expand their vocabulary, and improve their ability of vocabulary application. Besides, the design offers more context including sentences and short passage for students to practice words flexibly.1. Guide students to understand and consolidate the meaning and usage of the vocabulary in the context, 2. Guide the students to use the unit topic vocabulary in a richer context3. Let the students sort out and accumulate the accumulated vocabulary, establishes the semantic connection between the vocabulary,4. Enable students to understand and master the vocabulary more effectivelyGuiding the Ss to use unit topic words and the sentence patterns in a richer context.Step1: Read the passage about chemical burns and fill in the blanks with the correct forms of the words in the box.
(2)平均數(shù)受數(shù)據(jù)中的極端值(2個95)影響較大,使平均數(shù)在估計總體時可靠性降低,10天的用水量有8天都在平均值以下。故用中位數(shù)來估計每天的用水量更合適。1、樣本的數(shù)字特征:眾數(shù)、中位數(shù)和平均數(shù);2、用樣本頻率分布直方圖估計樣本的眾數(shù)、中位數(shù)、平均數(shù)。(1)眾數(shù)規(guī)定為頻率分布直方圖中最高矩形下端的中點;(2)中位數(shù)兩邊的直方圖的面積相等;(3)頻率分布直方圖中每個小矩形的面積與小矩形底邊中點的橫坐標之積相加,就是樣本數(shù)據(jù)的估值平均數(shù)。學生回顧本節(jié)課知識點,教師補充。 讓學生掌握本節(jié)課知識點,并能夠靈活運用。
等式性質(zhì)與不等式性質(zhì)是高中數(shù)學的主要內(nèi)容之一,在高中數(shù)學中占有重要地位,它是刻畫現(xiàn)實世界中量與量之間關系的有效數(shù)學模型,在現(xiàn)實生活中有著廣泛的應,有著重要的實際意義.同時等式性質(zhì)與不等式性質(zhì)也為學生以后順利學習基本不等式起到重要的鋪墊.課程目標1. 掌握等式性質(zhì)與不等式性質(zhì)以及推論,能夠運用其解決簡單的問題.2. 進一步掌握作差、作商、綜合法等比較法比較實數(shù)的大小. 3. 通過教學培養(yǎng)學生合作交流的意識和大膽猜測、樂于探究的良好思維品質(zhì)。數(shù)學學科素養(yǎng)1.數(shù)學抽象:不等式的基本性質(zhì);2.邏輯推理:不等式的證明;3.數(shù)學運算:比較多項式的大小及重要不等式的應用;4.數(shù)據(jù)分析:多項式的取值范圍,許將單項式的范圍之一求出,然后相加或相乘.(將減法轉(zhuǎn)化為加法,將除法轉(zhuǎn)化為乘法);5.數(shù)學建模:運用類比的思想有等式的基本性質(zhì)猜測不等式的基本性質(zhì)。
本節(jié)通過一些函數(shù)模型的實例,讓學生感受建立函數(shù)模型的過程和方法,體會函數(shù)在數(shù)學和其他學科中的廣泛應用,進一步認識到函數(shù)是描述客觀世界變化規(guī)律的基本數(shù)學模型,能初步運用函數(shù)思想解決一些生活中的簡單問題。課程目標1.能利用已知函數(shù)模型求解實際問題.2.能自建確定性函數(shù)模型解決實際問題.數(shù)學學科素養(yǎng)1.數(shù)學抽象:建立函數(shù)模型,把實際應用問題轉(zhuǎn)化為數(shù)學問題;2.邏輯推理:通過數(shù)據(jù)分析,確定合適的函數(shù)模型;3.數(shù)學運算:解答數(shù)學問題,求得結(jié)果;4.數(shù)據(jù)分析:把數(shù)學結(jié)果轉(zhuǎn)譯成具體問題的結(jié)論,做出解答;5.數(shù)學建模:借助函數(shù)模型,利用函數(shù)的思想解決現(xiàn)實生活中的實際問題.重點:利用函數(shù)模型解決實際問題;難點:數(shù)模型的構造與對數(shù)據(jù)的處理.
本節(jié)課選自《普通高中課程標準實驗教科書數(shù)學必修1本(A版)》的第五章的4.5.3函數(shù)模型的應用。函數(shù)模型及其應用是中學重要內(nèi)容之一,又是數(shù)學與生活實踐相互銜接的樞紐,特別在應用意識日益加深的今天,函數(shù)模型的應用實質(zhì)是揭示了客觀世界中量的相互依存有互有制約的關系,因而函數(shù)模型的應用舉例有著不可替代的重要位置,又有重要的現(xiàn)實意義。本節(jié)課要求學生利用給定的函數(shù)模型或建立函數(shù)模型解決實際問題,并對給定的函數(shù)模型進行簡單的分析評價,發(fā)展學生數(shù)學建模、數(shù)學直觀、數(shù)學抽象、邏輯推理的核心素養(yǎng)。1. 能建立函數(shù)模型解決實際問題.2.了解擬合函數(shù)模型并解決實際問題.3.通過本節(jié)內(nèi)容的學習,使學生認識函數(shù)模型的作用,提高學生數(shù)學建模,數(shù)據(jù)分析的能力. a.數(shù)學抽象:由實際問題建立函數(shù)模型;b.邏輯推理:選擇合適的函數(shù)模型;c.數(shù)學運算:運用函數(shù)模型解決實際問題;
1.確定研究對象,明確哪個是解釋變量,哪個是響應變量;2.由經(jīng)驗確定非線性經(jīng)驗回歸方程的模型;3.通過變換,將非線性經(jīng)驗回歸模型轉(zhuǎn)化為線性經(jīng)驗回歸模型;4.按照公式計算經(jīng)驗回歸方程中的參數(shù),得到經(jīng)驗回歸方程;5.消去新元,得到非線性經(jīng)驗回歸方程;6.得出結(jié)果后分析殘差圖是否有異常 .跟蹤訓練1.一只藥用昆蟲的產(chǎn)卵數(shù)y與一定范圍內(nèi)的溫度x有關,現(xiàn)收集了6組觀測數(shù)據(jù)列于表中: 經(jīng)計算得: 線性回歸殘差的平方和: ∑_(i=1)^6?〖(y_i-(y_i ) ?)〗^2=236,64,e^8.0605≈3167.其中 分別為觀測數(shù)據(jù)中的溫度和產(chǎn)卵數(shù),i=1,2,3,4,5,6.(1)若用線性回歸模型擬合,求y關于x的回歸方程 (精確到0.1);(2)若用非線性回歸模型擬合,求得y關于x回歸方程為 且相關指數(shù)R2=0.9522. ①試與(1)中的線性回歸模型相比較,用R2說明哪種模型的擬合效果更好 ?②用擬合效果好的模型預測溫度為35℃時該種藥用昆蟲的產(chǎn)卵數(shù).(結(jié)果取整數(shù)).
新知探究我們知道,等差數(shù)列的特征是“從第2項起,每一項與它的前一項的差都等于同一個常數(shù)” 。類比等差數(shù)列的研究思路和方法,從運算的角度出發(fā),你覺得還有怎樣的數(shù)列是值得研究的?1.兩河流域發(fā)掘的古巴比倫時期的泥版上記錄了下面的數(shù)列:9,9^2,9^3,…,9^10; ①100,100^2,100^3,…,100^10; ②5,5^2,5^3,…,5^10. ③2.《莊子·天下》中提到:“一尺之錘,日取其半,萬世不竭.”如果把“一尺之錘”的長度看成單位“1”,那么從第1天開始,每天得到的“錘”的長度依次是1/2,1/4,1/8,1/16,1/32,… ④3.在營養(yǎng)和生存空間沒有限制的情況下,某種細菌每20 min 就通過分裂繁殖一代,那么一個這種細菌從第1次分裂開始,各次分裂產(chǎn)生的后代個數(shù)依次是2,4,8,16,32,64,… ⑤4.某人存入銀行a元,存期為5年,年利率為 r ,那么按照復利,他5年內(nèi)每年末得到的本利和分別是a(1+r),a〖(1+r)〗^2,a〖(1+r)〗^3,a〖(1+r)〗^4,a〖(1+r)〗^5 ⑥
二、典例解析例4. 用 10 000元購買某個理財產(chǎn)品一年.(1)若以月利率0.400%的復利計息,12個月能獲得多少利息(精確到1元)?(2)若以季度復利計息,存4個季度,則當每季度利率為多少時,按季結(jié)算的利息不少于按月結(jié)算的利息(精確到10^(-5))?分析:復利是指把前一期的利息與本金之和算作本金,再計算下一期的利息.所以若原始本金為a元,每期的利率為r ,則從第一期開始,各期的本利和a , a(1+r),a(1+r)^2…構成等比數(shù)列.解:(1)設這筆錢存 n 個月以后的本利和組成一個數(shù)列{a_n },則{a_n }是等比數(shù)列,首項a_1=10^4 (1+0.400%),公比 q=1+0.400%,所以a_12=a_1 q^11 〖=10〗^4 (1+0.400%)^12≈10 490.7.所以,12個月后的利息為10 490.7-10^4≈491(元).解:(2)設季度利率為 r ,這筆錢存 n 個季度以后的本利和組成一個數(shù)列{b_n },則{b_n }也是一個等比數(shù)列,首項 b_1=10^4 (1+r),公比為1+r,于是 b_4=10^4 (1+r)^4.
我們知道數(shù)列是一種特殊的函數(shù),在函數(shù)的研究中,我們在理解了函數(shù)的一般概念,了解了函數(shù)變化規(guī)律的研究內(nèi)容(如單調(diào)性,奇偶性等)后,通過研究基本初等函數(shù)不僅加深了對函數(shù)的理解,而且掌握了冪函數(shù),指數(shù)函數(shù),對數(shù)函數(shù),三角函數(shù)等非常有用的函數(shù)模型。類似地,在了解了數(shù)列的一般概念后,我們要研究一些具有特殊變化規(guī)律的數(shù)列,建立它們的通項公式和前n項和公式,并應用它們解決實際問題和數(shù)學問題,從中感受數(shù)學模型的現(xiàn)實意義與應用,下面,我們從一類取值規(guī)律比較簡單的數(shù)列入手。新知探究1.北京天壇圜丘壇,的地面有十板布置,最中間是圓形的天心石,圍繞天心石的是9圈扇環(huán)形的石板,從內(nèi)到外各圈的示板數(shù)依次為9,18,27,36,45,54,63,72,81 ①2.S,M,L,XL,XXL,XXXL型號的女裝上對應的尺碼分別是38,40,42,44,46,48 ②3.測量某地垂直地面方向上海拔500米以下的大氣溫度,得到從距離地面20米起每升高100米處的大氣溫度(單位℃)依次為25,24,23,22,21 ③
二、典例解析例3.某公司購置了一臺價值為220萬元的設備,隨著設備在使用過程中老化,其價值會逐年減少.經(jīng)驗表明,每經(jīng)過一年其價值會減少d(d為正常數(shù))萬元.已知這臺設備的使用年限為10年,超過10年 ,它的價值將低于購進價值的5%,設備將報廢.請確定d的范圍.分析:該設備使用n年后的價值構成數(shù)列{an},由題意可知,an=an-1-d (n≥2). 即:an-an-1=-d.所以{an}為公差為-d的等差數(shù)列.10年之內(nèi)(含10年),該設備的價值不小于(220×5%=)11萬元;10年后,該設備的價值需小于11萬元.利用{an}的通項公式列不等式求解.解:設使用n年后,這臺設備的價值為an萬元,則可得數(shù)列{an}.由已知條件,得an=an-1-d(n≥2).所以數(shù)列{an}是一個公差為-d的等差數(shù)列.因為a1=220-d,所以an=220-d+(n-1)(-d)=220-nd. 由題意,得a10≥11,a11<11. 即:{█("220-10d≥11" @"220-11d<11" )┤解得19<d≤20.9所以,d的求值范圍為19<d≤20.9
情景導學古語云:“勤學如春起之苗,不見其增,日有所長”如果對“春起之苗”每日用精密儀器度量,則每日的高度值按日期排在一起,可組成一個數(shù)列. 那么什么叫數(shù)列呢?二、問題探究1. 王芳從一歲到17歲,每年生日那天測量身高,將這些身高數(shù)據(jù)(單位:厘米)依次排成一列數(shù):75,87,96,103,110,116,120,128,138,145,153,158,160,162,163,165,168 ①記王芳第i歲的身高為 h_i ,那么h_1=75 , h_2=87, 〖"…" ,h〗_17=168.我們發(fā)現(xiàn)h_i中的i反映了身高按歲數(shù)從1到17的順序排列時的確定位置,即h_1=75 是排在第1位的數(shù),h_2=87是排在第2位的數(shù)〖"…" ,h〗_17 =168是排在第17位的數(shù),它們之間不能交換位置,所以①具有確定順序的一列數(shù)。2. 在兩河流域發(fā)掘的一塊泥板(編號K90,約生產(chǎn)于公元前7世紀)上,有一列依次表示一個月中從第1天到第15天,每天月亮可見部分的數(shù):5,10,20,40,80,96,112,128,144,160,176,192,208,224,240. ②
1.判斷正誤(正確的打“√”,錯誤的打“×”)(1)函數(shù)f (x)在區(qū)間(a,b)上都有f ′(x)<0,則函數(shù)f (x)在這個區(qū)間上單調(diào)遞減. ( )(2)函數(shù)在某一點的導數(shù)越大,函數(shù)在該點處的切線越“陡峭”. ( )(3)函數(shù)在某個區(qū)間上變化越快,函數(shù)在這個區(qū)間上導數(shù)的絕對值越大.( )(4)判斷函數(shù)單調(diào)性時,在區(qū)間內(nèi)的個別點f ′(x)=0,不影響函數(shù)在此區(qū)間的單調(diào)性.( )[解析] (1)√ 函數(shù)f (x)在區(qū)間(a,b)上都有f ′(x)<0,所以函數(shù)f (x)在這個區(qū)間上單調(diào)遞減,故正確.(2)× 切線的“陡峭”程度與|f ′(x)|的大小有關,故錯誤.(3)√ 函數(shù)在某個區(qū)間上變化的快慢,和函數(shù)導數(shù)的絕對值大小一致.(4)√ 若f ′(x)≥0(≤0),則函數(shù)f (x)在區(qū)間內(nèi)單調(diào)遞增(減),故f ′(x)=0不影響函數(shù)單調(diào)性.[答案] (1)√ (2)× (3)√ (4)√例1. 利用導數(shù)判斷下列函數(shù)的單調(diào)性:(1)f(x)=x^3+3x; (2) f(x)=sinx-x,x∈(0,π); (3)f(x)=(x-1)/x解: (1) 因為f(x)=x^3+3x, 所以f^' (x)=〖3x〗^2+3=3(x^2+1)>0所以f(x)=x^3+3x ,函數(shù)在R上單調(diào)遞增,如圖(1)所示
求函數(shù)的導數(shù)的策略(1)先區(qū)分函數(shù)的運算特點,即函數(shù)的和、差、積、商,再根據(jù)導數(shù)的運算法則求導數(shù);(2)對于三個以上函數(shù)的積、商的導數(shù),依次轉(zhuǎn)化為“兩個”函數(shù)的積、商的導數(shù)計算.跟蹤訓練1 求下列函數(shù)的導數(shù):(1)y=x2+log3x; (2)y=x3·ex; (3)y=cos xx.[解] (1)y′=(x2+log3x)′=(x2)′+(log3x)′=2x+1xln 3.(2)y′=(x3·ex)′=(x3)′·ex+x3·(ex)′=3x2·ex+x3·ex=ex(x3+3x2).(3)y′=cos xx′=?cos x?′·x-cos x·?x?′x2=-x·sin x-cos xx2=-xsin x+cos xx2.跟蹤訓練2 求下列函數(shù)的導數(shù)(1)y=tan x; (2)y=2sin x2cos x2解析:(1)y=tan x=sin xcos x,故y′=?sin x?′cos x-?cos x?′sin x?cos x?2=cos2x+sin2xcos2x=1cos2x.(2)y=2sin x2cos x2=sin x,故y′=cos x.例5 日常生活中的飲用水通常是經(jīng)過凈化的,隨著水的純凈度的提高,所需進化費用不斷增加,已知將1t水進化到純凈度為x%所需費用(單位:元),為c(x)=5284/(100-x) (80<x<100)求進化到下列純凈度時,所需進化費用的瞬時變化率:(1) 90% ;(2) 98%解:凈化費用的瞬時變化率就是凈化費用函數(shù)的導數(shù);c^' (x)=〖(5284/(100-x))〗^'=(5284^’×(100-x)-"5284 " 〖(100-x)〗^’)/〖(100-x)〗^2 =(0×(100-x)-"5284 " ×(-1))/〖(100-x)〗^2 ="5284 " /〖(100-x)〗^2
新知探究前面我們研究了兩類變化率問題:一類是物理學中的問題,涉及平均速度和瞬時速度;另一類是幾何學中的問題,涉及割線斜率和切線斜率。這兩類問題來自不同的學科領域,但在解決問題時,都采用了由“平均變化率”逼近“瞬時變化率”的思想方法;問題的答案也是一樣的表示形式。下面我們用上述思想方法研究更一般的問題。探究1: 對于函數(shù)y=f(x) ,設自變量x從x_0變化到x_0+ ?x ,相應地,函數(shù)值y就從f(x_0)變化到f(〖x+x〗_0) 。這時, x的變化量為?x,y的變化量為?y=f(x_0+?x)-f(x_0)我們把比值?y/?x,即?y/?x=(f(x_0+?x)-f(x_0)" " )/?x叫做函數(shù)從x_0到x_0+?x的平均變化率。1.導數(shù)的概念如果當Δx→0時,平均變化率ΔyΔx無限趨近于一個確定的值,即ΔyΔx有極限,則稱y=f (x)在x=x0處____,并把這個________叫做y=f (x)在x=x0處的導數(shù)(也稱為__________),記作f ′(x0)或________,即
問題二:上述問題中,甲、乙的平均數(shù)、中位數(shù)、眾數(shù)相同,但二者的射擊成績存在差異,那么,如何度量這種差異呢?我們可以利用極差進行度量。根據(jù)上述數(shù)據(jù)計算得:甲的極差=10-4=6 乙的極差=9-5=4極差在一定程度上刻畫了數(shù)據(jù)的離散程度。由極差發(fā)現(xiàn)甲的成績波動范圍比乙的大。但由于極差只使用了數(shù)據(jù)中最大、最小兩個值的信息,所含的信息量很少。也就是說,極差度量出的差異誤差較大。問題三:你還能想出其他刻畫數(shù)據(jù)離散程度的辦法嗎?我們知道,如果射擊的成績很穩(wěn)定,那么大多數(shù)的射擊成績離平均成績不會太遠;相反,如果射擊的成績波動幅度很大,那么大多數(shù)的射擊成績離平均成績會比較遠。因此,我們可以通過這兩組射擊成績與它們的平均成績的“平均距離”來度量成績的波動幅度。
可以通過下面的步驟計算一組n個數(shù)據(jù)的第p百分位數(shù):第一步:按從小到大排列原始數(shù)據(jù);第二步:計算i=n×p%;第三步:若i不是整數(shù),而大于i的比鄰整數(shù)位j,則第p百分位數(shù)為第j項數(shù)據(jù);若i是整數(shù),則第p百分位數(shù)為第i項與第i+1項的平均數(shù)。我們在初中學過的中位數(shù),相當于是第50百分位數(shù)。在實際應用中,除了中位數(shù)外,常用的分位數(shù)還有第25百分位數(shù),第75百分位數(shù)。這三個分位數(shù)把一組由小到大排列后的數(shù)據(jù)分成四等份,因此稱為四分位數(shù)。其中第25百分位數(shù)也稱為第一四分位數(shù)或下四分位數(shù)等,第75百分位數(shù)也稱為第三四分位數(shù)或上四分位數(shù)等。另外,像第1百分位數(shù),第5百分位數(shù),第95百分位數(shù),和第99百分位數(shù)在統(tǒng)計中也經(jīng)常被使用。例2、根據(jù)下列樣本數(shù)據(jù),估計樹人中學高一年級女生第25,50,75百分位數(shù)。